Optimal. Leaf size=78 \[ \frac{\sin ^3(e+f x) \cos ^2(e+f x)^{\frac{n+1}{2}} (b \tan (e+f x))^{n+1} \, _2F_1\left (\frac{n+1}{2},\frac{n+4}{2};\frac{n+6}{2};\sin ^2(e+f x)\right )}{b f (n+4)} \]
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Rubi [A] time = 0.084357, antiderivative size = 78, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.105, Rules used = {2602, 2577} \[ \frac{\sin ^3(e+f x) \cos ^2(e+f x)^{\frac{n+1}{2}} (b \tan (e+f x))^{n+1} \, _2F_1\left (\frac{n+1}{2},\frac{n+4}{2};\frac{n+6}{2};\sin ^2(e+f x)\right )}{b f (n+4)} \]
Antiderivative was successfully verified.
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Rule 2602
Rule 2577
Rubi steps
\begin{align*} \int \sin ^3(e+f x) (b \tan (e+f x))^n \, dx &=\frac{\left (\cos ^{1+n}(e+f x) \sin ^{-1-n}(e+f x) (b \tan (e+f x))^{1+n}\right ) \int \cos ^{-n}(e+f x) \sin ^{3+n}(e+f x) \, dx}{b}\\ &=\frac{\cos ^2(e+f x)^{\frac{1+n}{2}} \, _2F_1\left (\frac{1+n}{2},\frac{4+n}{2};\frac{6+n}{2};\sin ^2(e+f x)\right ) \sin ^3(e+f x) (b \tan (e+f x))^{1+n}}{b f (4+n)}\\ \end{align*}
Mathematica [C] time = 2.85598, size = 456, normalized size = 5.85 \[ \frac{4 (n+4) \sin \left (\frac{1}{2} (e+f x)\right ) \sin ^3(e+f x) \cos ^3\left (\frac{1}{2} (e+f x)\right ) \left (F_1\left (\frac{n}{2}+1;n,3;\frac{n}{2}+2;\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )-F_1\left (\frac{n}{2}+1;n,4;\frac{n}{2}+2;\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )\right ) (b \tan (e+f x))^n}{f (n+2) \left (-2 (n+4) \cos ^2\left (\frac{1}{2} (e+f x)\right ) F_1\left (\frac{n}{2}+1;n,4;\frac{n}{2}+2;\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )+2 (\cos (e+f x)-1) \left (3 F_1\left (\frac{n}{2}+2;n,4;\frac{n}{2}+3;\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )-4 F_1\left (\frac{n}{2}+2;n,5;\frac{n}{2}+3;\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )+n \left (F_1\left (\frac{n}{2}+2;n+1,4;\frac{n}{2}+3;\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )-F_1\left (\frac{n}{2}+2;n+1,3;\frac{n}{2}+3;\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )\right )\right )+(n+4) (\cos (e+f x)+1) F_1\left (\frac{n}{2}+1;n,3;\frac{n}{2}+2;\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )\right )} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.778, size = 0, normalized size = 0. \begin{align*} \int \left ( \sin \left ( fx+e \right ) \right ) ^{3} \left ( b\tan \left ( fx+e \right ) \right ) ^{n}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (b \tan \left (f x + e\right )\right )^{n} \sin \left (f x + e\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-{\left (\cos \left (f x + e\right )^{2} - 1\right )} \left (b \tan \left (f x + e\right )\right )^{n} \sin \left (f x + e\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (b \tan \left (f x + e\right )\right )^{n} \sin \left (f x + e\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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